(2-y)^2=-3y(2-y)

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Solution for (2-y)^2=-3y(2-y) equation: 



(2-y)^2=-3y(2-y)

We move all terms to the left:

(2-y)^2-(-3y(2-y))=0

We add all the numbers together, and all the variables

(-1y+2)^2-(-3y(-1y+2))=0



We calculate terms in parentheses: -(-3y(-1y+2)), so:

-3y(-1y+2)

We multiply parentheses

3y^2-6y

Back to the equation:

-(3y^2-6y)



We get rid of parentheses

-3y^2+(-1y+2)^2+6y=0

We add all the numbers together, and all the variables

-3y^2+6y+(-1y+2)^2=0

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